 # Hypothesis Identification Article Analysis

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This analysis is to explain whether the hypothesis was or accepted and what is the implication of the finding are in the study. The study will use the two- sample Z test to hypothesize the imaging of the appearance of metastatic tumors and primary ovarian tumors in this analysis. The H o is the null hypothesis will be usedto assume there is not any association between the prediction and the outcome of any variable in this population study. The alternative hypothesis H1 is to assume that there is an association between the prediction and the outcome in a population study. In hypotheses an explanatory or independent variable is a variable that manipulates the effect on the outcome of the dependent variable Zou , H.K., Fielding, R.J., Silverman, G.S., and Tempany, C.M.C. [, (2003).

The two- sample Z test is used to hypothesize the imaging of the appearance of metastatic tumors and primary ovarian tumors. This is done to see if the damage to the ovary is the same or different. Data was gathered from 280 patients with ovarian masses. Rejected. The patients underwent Ultrasound ( US) in the Radiologic Diagnostic Oncology Group (RDOG) The test was to determine the difference in the underlying proportion of a statistical hypotheses test was given in five steps. The five steps that was done to reject or fail to reject the hypotheses. There are not any difference in the masses between the multilocular metastatic tumors (π 1) than the multilocular ovarian tumors (π ). The primary and secondary cancers are n1 �€"n-2 with H1 to follow. The only difference in these proportion is that one is lesser than or greater than the other meaning that n1-n 2 ≠ 0 in this hypothesis testing that is atwo=tailed hypothesis Then the test statistics of z is to be calculated to be 2.27 on the basis of the z-test. This is to compare the two independent proportions rejected Zou , H.K., Fielding, R.J., Silverman, G.S., & Tempany, C.M.C , (2003)

The p-value will =02 with a sum of the two- tailed probabilities with a standard normal distribution. The standard distribution is beyond 2.27. Ho is rejected because the p-value is 0.2 and also small. This makes it less than the significance level σ of 0.5. There are only a slight significance difference between the proportions of the masses of the multilocular metastatic tumors and the multilocular primary ovarian tumors in the 280 patients in the study the null (Ho) was usedfor the testing of the hypothesis and was not rejected Zou , H.K., Fielding, R.J., Silverman, G.S., & Tempany, C.M.C., (2003)

Reference

Zou ,H.K., Fielding, R.J., Silverman, G.S., & Tempany, C.M.C., (2003) Radiology Hypothesis Testing I: Proportions Radiology Retrieved on March 18, 2011 from RES342�€"Research and Evaluation Course Web-site

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