Statistic Case
Essay by Woxman • April 27, 2012 • Essay • 571 Words (3 Pages) • 1,414 Views
Total students = 100
Total left handed = 10
Total right handed = 100 - 10 = 90
= 90
Right handed students
p ( R1 ) x ( 2 R handed )
90 /100 x 89 / 99 = 8010 / 9900 = 0.8091
= 0 .8091
(b) Left handed students
Total left handed students = 10
P ( L1 x (2L ) = 10/100 x 9/99
= 0.1 x 0.0909 = 0.0091
= 0.0091
( c) Right handed other left handed
P ( R1) other left handed = P ( R 1 ) and ( L2 ) or P ( L1 ) and P( R2 )
P = 90/100 x P = 10/99 or 10/100 x 90/99
= ( 0.9 x 0.01010 ) + (0.1 X 0.9091)
= 0.0909 + 0.09091 = 0.1818
= 0.1818
(D) At least right handed
1a + 1c total
0.8091 + 0.1818 = 0.9909
=0.9909
(2) Find the joint propability
P ( AB ) = P ( A ) P ( B/A )
P = ( A ) = 0.4 P ( B/A ) = 0.3P ( AB = ( 0.4 x 0.3 ) = 0.12
= 0.12
(3) Total possible outcome of dice 6x 6 = 36
Propability first throw = 2 = 1
Probability second throw = 1 = 1
Probability for 2 throws = 1/6 x 1/6 = 1/36
= 1/36
(b ) No of ways sum = 7
1 +6 = 7
2+ 5 = 7
3+ 4 = 7
4+ 3 = 7
5+ 2 = 7
6+ 1 =7
Probability total number = 7
= 6/36 = 1/6
= 1/6
(4 ) Coined tossed 4 times outcome recorded for each toss.
HHHT TTTT
HHHH TTTH
HHTH TTHT
HHTT TTHT
HTHT THTH
HTTH THHT
HTTT
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